What is the sum from n=0 to infinity of (1/13)^n ?

The sum from n=0 to infinity of (1/13)^n is 13/12

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sum from n=0 to infinity of (1/13)^n

n = 0 \sum \infty (\frac{1}{13})^{n}

\frac{13}{12}

Solution steps

n = 0 \sum \infty (\frac{1}{13})^{n}

Apply Series Geometric Test:

\frac{13}{12}

= \frac{13}{12}

n = 6 \sum \infty \frac{1}{( n - 5 ) ^{2}}

n = 1 \sum \infty \frac{2 ^{n} 3 ^{n}}{n}

n = 1 \sum \infty \frac{5}{3 ^{n - 1}}

n = 1 \sum \infty \frac{π}{n ^{2}}

n = 1 \sum \infty (\frac{- 1}{3})^{n}

What is the sum from n=0 to infinity of (1/13)^n ?
The sum from n=0 to infinity of (1/13)^n is 13/12