What is the tangent of y=(4x)/(x+2),(2,2) ?

The tangent of y=(4x)/(x+2),(2,2) is y= 1/2 x+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=(4x)/(x+2),(2,2)

tangent of

y = \frac{4 x}{x + 2}, (2, 2)

y = \frac{1}{2} x + 1

Solution steps

Find the slope of

y = \frac{4 x}{x + 2} : \frac{d y}{d x} = \frac{8}{( x + 2 ) ^{2}}

Compute the slope of

y = \frac{4 x}{x + 2}

(2, 2) : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(2, 2) : y = \frac{1}{2} x + 1

y = \frac{1}{2} x + 1

\int \frac{ln ( 6 x )}{x ^{8}} d x

x \to 1 lim (csc (\frac{x}{2}))

\int \frac{- x}{1 + x ^{2}} d x

n = 1 \sum \infty \frac{1}{n + 10}

\int \frac{0.4}{1 - x ^{2}} d x

What is the tangent of y=(4x)/(x+2),(2,2) ?
The tangent of y=(4x)/(x+2),(2,2) is y= 1/2 x+1