What is the first (4sin(x))^' ?

The first (4sin(x))^' is 4cos(x)

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(4sin(x))^'

(4 sin (x))^{^{'}}

4 cos (x)

Solution steps

(4 sin (x))^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 (sin (x))^{^{'}}

Apply the common derivative:

(sin (x))^{'} = cos (x)

= 4 cos (x)

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