What is (\partial)/(\partial u)(u/(4(v-w)^{3/2)}) ?

The answer to (\partial)/(\partial u)(u/(4(v-w)^{3/2)}) is 1/(4(v-w)^{3/2)}

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(\partial)/(\partial u)(u/(4(v-w)^{3/2)})

\frac{\partial}{\partial u} (\frac{u}{4 ( v - w ) ^{\frac{3}{2}}})

\frac{1}{4 ( v - w ) ^{\frac{3}{2}}}

Solution steps

\frac{\partial}{\partial u} (\frac{u}{4 ( v - w ) ^{\frac{3}{2}}})

Treat

v, w

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4 ( v - w ) ^{\frac{3}{2}}} \frac{\partial}{\partial u} (u)

Apply the common derivative:

\frac{\partial}{\partial u} (u) = 1

= \frac{1}{4 ( v - w ) ^{\frac{3}{2}}} \cdot 1

Simplify

= \frac{1}{4 ( v - w ) ^{\frac{3}{2}}}

\frac{d y}{d x} = 1 + 5 y

7 + 4 x^{2} - 2 x^{3}

x \to 1 - lim (e^{x})

\frac{x + 6}{x + 2}

y^{^{'}} + \frac{1}{x} y = - 4 y^{2}

What is (\partial)/(\partial u)(u/(4(v-w)^{3/2)}) ?
The answer to (\partial)/(\partial u)(u/(4(v-w)^{3/2)}) is 1/(4(v-w)^{3/2)}