What is the sum from n=0 to infinity of ((-5)^n)/n ?

The sum from n=0 to infinity of ((-5)^n)/n is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of ((-5)^n)/n

n = 0 \sum \infty \frac{( - 5 ) ^{n}}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{( - 5 ) ^{n}}{n}

Apply Series Ratio Test:

diverges

= diverges

n = 0 \sum \infty \frac{( 6 ^{n} )}{n !}

n = 0 \sum \infty ln (3 - n)

n = 0 \sum \infty \frac{1}{3 ^{n} - 1}

n = 0 \sum \infty 0.52 (0.01)^{n}

n = 1 \sum \infty 2 + \frac{cos ( n )}{n}

What is the sum from n=0 to infinity of ((-5)^n)/n ?
The sum from n=0 to infinity of ((-5)^n)/n is diverges