What is the sum from k=0 to infinity of (-1/4)^k ?

The sum from k=0 to infinity of (-1/4)^k is 4/5

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sum from k=0 to infinity of (-1/4)^k

k = 0 \sum \infty (- \frac{1}{4})^{k}

\frac{4}{5}

Solution steps

k = 0 \sum \infty (- \frac{1}{4})^{k}

Apply Series Geometric Test:

\frac{4}{5}

= \frac{4}{5}

n = 1 \sum \infty 6^{n}

n = 0 \sum \infty \frac{7}{n}

n = 1 \sum \infty n! (- e)^{- 6 n}

n = 0 \sum \infty 2^{2 - n} \cdot 3^{n}

n = 0 \sum \infty (n + 1) (1)^{n}

What is the sum from k=0 to infinity of (-1/4)^k ?
The sum from k=0 to infinity of (-1/4)^k is 4/5