Solution
Solution
Solution steps
Apply Series Comparison Test:converges
Popular Examples
sum from n=1 to infinity of n(9/8)^nsum from n=1 to infinity of (5/12)^nsum from n=1 to infinity of (-2)^{-n}sum from n=1 to infinity of 1/(6^{n-1)}sum from n=5 to infinity of 1/((n-4)^3)
Frequently Asked Questions (FAQ)
What is the sum from n=0 to infinity of 1/(n^2+9) ?
The sum from n=0 to infinity of 1/(n^2+9) is converges