What is the sum from n=0 to infinity of (0.25)^n ?

The sum from n=0 to infinity of (0.25)^n is 1.33333…

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sum from n=0 to infinity of (0.25)^n

n = 0 \sum \infty (0.25)^{n}

1.33333 \dots

Solution steps

n = 0 \sum \infty 0.2 5^{n}

Apply Series Geometric Test:

1.33333 \dots

= 1.33333 \dots

n = 0 \sum \infty \frac{n}{7 ^{n}}

n = 5 \sum \infty \frac{1}{( n - 2 ) ^{4}}

n = 2 \sum \infty 9 e^{- 2 n}

n = 0 \sum \infty e^{2 l n (n)}

k = 1 \sum \infty \frac{6}{k} - \frac{6}{k + 1}

What is the sum from n=0 to infinity of (0.25)^n ?
The sum from n=0 to infinity of (0.25)^n is 1.33333…