What is the sum from n=1 to infinity of ((-1)/7)^n ?

The sum from n=1 to infinity of ((-1)/7)^n is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of ((-1)/7)^n

n = 1 \sum \infty (\frac{- 1}{7})^{n}

converges

Solution steps

n = 1 \sum \infty (\frac{- 1}{7})^{n}

Apply Series Ratio Test:

converges

= converges

n = 0 \sum \infty (\frac{1}{2})^{n - 2}

n = 0 \sum \infty (\frac{- 1}{4})^{n}

n = 2 \sum \infty \frac{1}{ln ( n ^{3} )}

n = 3 \sum \infty 5 (\frac{4}{9})^{n}

n = 1 \sum \infty \frac{5}{n ^{2} + 121}

What is the sum from n=1 to infinity of ((-1)/7)^n ?
The sum from n=1 to infinity of ((-1)/7)^n is converges