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Popular >

d/(dθ)(-n/2ln(2pi)-n/2ln(θ^2))

Solution

\frac{d}{d θ} (- \frac{n}{2} \cdot ln (2 π) - \frac{n}{2} \cdot ln (θ^{2}))

Solution

- \frac{n}{θ}

Solution steps

\frac{d}{d θ} (- \frac{n}{2} ln (2 π) - \frac{n}{2} ln (θ^{2}))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d θ} (\frac{n}{2} ln (2 π)) - \frac{d}{d θ} (\frac{n}{2} ln (θ^{2}))

\frac{d}{d θ} (\frac{n}{2} ln (2 π)) = 0

\frac{d}{d θ} (\frac{n}{2} ln (θ^{2})) = \frac{n}{θ}

= - 0 - \frac{n}{θ}

Simplify

= - \frac{n}{θ}

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Frequently Asked Questions (FAQ)

What is the d/(dθ)(-n/2*ln(2pi)-n/2*ln(θ^2)) ?
The d/(dθ)(-n/2*ln(2pi)-n/2*ln(θ^2)) is -n/θ
What is the first d/(dθ)(-n/2*ln(2pi)-n/2*ln(θ^2)) ?
The first d/(dθ)(-n/2*ln(2pi)-n/2*ln(θ^2)) is -n/θ