Solution
Solution
Solution steps
Apply Series Limit Comparison Test:diverges
Popular Examples
sum from n=0 to infinity of 2^{n/2}sum from n=1 to infinity of (1/2)^{n-2}sum from k=1 to infinity of 6(1/5)^{k-1}sum from n=3 to infinity of 7/(3ln(n))sum from n=1 to infinity of 1/(n(n^2+1))
Frequently Asked Questions (FAQ)
What is the sum from n=1 to infinity of 1/(4+3n) ?
The sum from n=1 to infinity of 1/(4+3n) is diverges