What is the sum from x=1 to infinity of (ln(x))/x ?

The sum from x=1 to infinity of (ln(x))/x is diverges

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sum from x=1 to infinity of (ln(x))/x

x = 1 \sum \infty \frac{ln ( x )}{x}

diverges

Solution steps

n = 1 \sum \infty \frac{ln ( n )}{n}

Apply Series Integral Test:

diverges

= diverges

n = 1 \sum \infty (\frac{2}{n})^{2}

n = 1 \sum \infty (\frac{2}{n})^{1}

n = 0 \sum \infty 3 + \frac{2}{n ^{4}}

n = 1 \sum \infty \frac{3}{n ^{9}}

n = 0 \sum \infty \frac{n ^{2}}{1 + 6 n}

What is the sum from x=1 to infinity of (ln(x))/x ?
The sum from x=1 to infinity of (ln(x))/x is diverges