What is the sum from n=1 to infinity of 1/(1(n+1)) ?

The sum from n=1 to infinity of 1/(1(n+1)) is diverges

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sum from n=1 to infinity of 1/(1(n+1))

n = 1 \sum \infty \frac{1}{1 ( n + 1 )}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{1 \cdot ( n + 1 )}

Simplify

= n = 1 \sum \infty \frac{1}{n + 1}

Apply Series Limit Comparison Test:

diverges

= diverges

n = 1 \sum \infty (\frac{2}{10})^{n}

n = 0 \sum \infty \frac{2}{3 n + 5}

n = 1 \sum \infty \frac{6 n}{e ^{n}}

n = 1 \sum \infty n

n = 0 \sum \infty \frac{1}{n 3 ^{n}}

What is the sum from n=1 to infinity of 1/(1(n+1)) ?
The sum from n=1 to infinity of 1/(1(n+1)) is diverges