What is the sum from n=1 to infinity of (n-1)^2 ?

The sum from n=1 to infinity of (n-1)^2 is diverges

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sum from n=1 to infinity of (n-1)^2

n = 1 \sum \infty (n - 1)^{2}

diverges

Solution steps

n = 1 \sum \infty (n - 1)^{2}

Apply Series Divergence Test:

diverges

= diverges

k = 1 \sum \infty \frac{2}{k} - \frac{2}{k + 1}

n = 0 \sum \infty \frac{3}{e ^{n}}

n = 0 \sum \infty π^{- n}

n = 1 \sum \infty \frac{n}{5 n ^{2} + 3}

n = 0 \sum \infty \frac{2}{n}

What is the sum from n=1 to infinity of (n-1)^2 ?
The sum from n=1 to infinity of (n-1)^2 is diverges