What is the sum from n=1 to infinity of e^n+e^{-n} ?

The sum from n=1 to infinity of e^n+e^{-n} is diverges

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sum from n=1 to infinity of e^n+e^{-n}

n = 1 \sum \infty e^{n} + e^{- n}

diverges

Solution steps

n = 1 \sum \infty e^{n} + e^{- n}

Apply Series Ratio Test:

diverges

= diverges

n = 1 \sum \infty \frac{n}{7 n ^{2} + 1}

n = 0 \sum \infty \frac{5}{4 ^{n} - 3 ^{n}}

n = 0 \sum \infty 7

n = 1 \sum \infty 8 n sin (\frac{7}{n})

n = 1 \sum \infty \frac{e ^{3 n}}{n !}

What is the sum from n=1 to infinity of e^n+e^{-n} ?
The sum from n=1 to infinity of e^n+e^{-n} is diverges