What is the sum from n=0 to infinity}(\sqrt{3 of)^n ?

The sum from n=0 to infinity}(\sqrt{3 of)^n is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity}(\sqrt{3 of)^n

n = 0 \sum \infty (3)^{n}

diverges

Solution steps

n = 0 \sum \infty (3)^{n}

Apply Series Geometric Test:

diverges

= diverges

k = 1 \sum \infty \frac{7}{k} - \frac{7}{k + 1}

n = 1 \sum \infty \frac{3}{4 n ^{2} + 4 n}

k = 1 \sum \infty \frac{2 ^{k}}{k ^{3}}

n = 1 \sum \infty n^{2} e^{- \frac{3}{n}}

n = 0 \sum \infty \frac{6}{n ^{3}}

What is the sum from n=0 to infinity}(\sqrt{3 of)^n ?
The sum from n=0 to infinity}(\sqrt{3 of)^n is diverges