What is the derivative of 4sqrt(x)-6/(\sqrt[3]{x^2}) ?

The derivative of 4sqrt(x)-6/(\sqrt[3]{x^2}) is 2/(sqrt(x))+4/(x^{5/3)}

What is the first derivative of 4sqrt(x)-6/(\sqrt[3]{x^2}) ?

The first derivative of 4sqrt(x)-6/(\sqrt[3]{x^2}) is 2/(sqrt(x))+4/(x^{5/3)}

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\frac{2}{x} + \frac{4}{x ^{\frac{5}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (4 x) = \frac{2}{x}

= \frac{2}{x} - (- \frac{4}{x ^{\frac{5}{3}}})

Simplify

= \frac{2}{x} + \frac{4}{x ^{\frac{5}{3}}}

\frac{d}{d x} ((e^{- x} - e^{3}) (e^{x} + e^{- 5}))

\frac{d ^{4}}{d x ^{4}} (e^{\frac{1}{x}})

y = ln (sin (x))

\frac{d}{d x} (x^{2} 7 x - 5)

\frac{d}{d x} (∣ x - 9 ∣)

What is the derivative of 4sqrt(x)-6/(\sqrt[3]{x^2}) ?
The derivative of 4sqrt(x)-6/(\sqrt[3]{x^2}) is 2/(sqrt(x))+4/(x^{5/3)}
What is the first derivative of 4sqrt(x)-6/(\sqrt[3]{x^2}) ?
The first derivative of 4sqrt(x)-6/(\sqrt[3]{x^2}) is 2/(sqrt(x))+4/(x^{5/3)}