What is the sum from n=2 to infinity of 2/n ?

The sum from n=2 to infinity of 2/n is diverges

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sum from n=2 to infinity of 2/n

n = 2 \sum \infty \frac{2}{n}

diverges

Solution steps

n = 2 \sum \infty \frac{2}{n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 2 \cdot n = 2 \sum \infty \frac{1}{n}

Apply Cauchy's Convergence Condition:

diverges

= 2 diverges

= diverges

n = 0 \sum \infty (\frac{1}{14})^{n}

n = 0 \sum \infty \frac{n}{1 + 5 n}

n = 1 \sum \infty \frac{1}{cos ^{2} ( n )}

n = 1 \sum \infty \frac{( n ^{2} )}{2 n}

n = 0 \sum \infty \frac{2}{n + 2}

What is the sum from n=2 to infinity of 2/n ?
The sum from n=2 to infinity of 2/n is diverges