What is the sum from k=3 to infinity of (k-1)/(2k+1) ?

The sum from k=3 to infinity of (k-1)/(2k+1) is diverges

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sum from k=3 to infinity of (k-1)/(2k+1)

k = 3 \sum \infty \frac{k - 1}{2 k + 1}

diverges

Solution steps

k = 3 \sum \infty \frac{k - 1}{2 k + 1}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty 5 (\frac{3}{2})^{n}

n = 1 \sum \infty 1 + sin^{2} (n)

n = 5 \sum \infty (\frac{2}{11})^{n}

n = 1 \sum \infty 4 (- \frac{1}{2})^{n}

k = 1 \sum \infty \frac{k - 5}{k + 2}

What is the sum from k=3 to infinity of (k-1)/(2k+1) ?
The sum from k=3 to infinity of (k-1)/(2k+1) is diverges