What is the sum from n=0 to infinity of n/(5n^3+1) ?

The sum from n=0 to infinity of n/(5n^3+1) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of n/(5n^3+1)

n = 0 \sum \infty \frac{n}{5 n ^{3} + 1}

converges

Solution steps

n = 0 \sum \infty \frac{n}{5 n ^{3} + 1}

Apply Series Comparison Test:

converges

= converges

n = 0 \sum \infty 9^{\frac{1}{n}}

n = 0 \sum \infty 3 (\frac{2}{5})^{n + 1}

n = 0 \sum \infty \frac{4}{3 + n}

n = 0 \sum \infty \frac{1}{5 + 6 n}

n = 1 \sum \infty \frac{1}{9 n - 1}

What is the sum from n=0 to infinity of n/(5n^3+1) ?
The sum from n=0 to infinity of n/(5n^3+1) is converges