What is the tangent of 1+sqrt((x\at (4.3))) ?

The tangent of 1+sqrt((x\at (4.3))) is y=(1.03682…)/(sqrt(a_{0))}x+1+1.03682…sqrt(a_{0)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 1+sqrt((x\at (4.3)))

tangent of

1 + (x at (4.3))

y = \frac{1.03682 \dots}{a _{0}} x + 1 + 1.03682 \dots a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 1 + 4.3 a_{0})

Find the slope of

y = 1 + x 4.3 : \frac{d y}{d x} = \frac{1.03682 \dots}{x}

Compute the slope of

y = 1 + x 4.3

x = a_{0} : m = \frac{1.03682 \dots}{a _{0}}

Find the line with slope m=

\frac{1.03682 \dots}{a _{0}}

and passing through

(a_{0}, 1 + 4.3 a_{0}) : y = \frac{1.03682 \dots}{a _{0}} x + 1 + 1.03682 \dots a_{0}

y = \frac{1.03682 \dots}{a _{0}} x + 1 + 1.03682 \dots a_{0}

\frac{\partial}{\partial z} (4 x z)

\frac{d}{d x} (\frac{x ^{2} + 2}{x ^{2} - 3})

y^{^{'}} - y = e^{x}

y = ln^{3} (a^{2} + 1)

2 x^{2} + 2, (1, 3)

What is the tangent of 1+sqrt((x\at (4.3))) ?
The tangent of 1+sqrt((x\at (4.3))) is y=(1.03682…)/(sqrt(a_{0))}x+1+1.03682…sqrt(a_{0)}