What is the sum from n=0 to infinity of | e/n | ?

The sum from n=0 to infinity of | e/n | is diverges

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sum from n=0 to infinity of | e/n |

n = 0 \sum \infty \frac{e}{n}

diverges

Solution steps

n = 1 \sum \infty \frac{e}{n}

Simplify

\frac{e}{n} : \frac{e}{∣ n ∣}

= n = 1 \sum \infty \frac{e}{∣ n ∣}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= e \cdot n = 1 \sum \infty \frac{1}{∣ n ∣}

Apply Series Limit Comparison Test:

diverges

= e diverges

= diverges

n = 0 \sum \infty \frac{7}{π ^{n}}

n = 1 \sum \infty sin (3 n)

n = 0 \sum \infty \frac{2}{( - 3 ) ^{n}}

n = 1 \sum \infty \frac{2}{3 n - 1}

n = 2 \sum \infty \frac{- 1}{ln ( n )}

What is the sum from n=0 to infinity of | e/n | ?
The sum from n=0 to infinity of | e/n | is diverges