What is the derivative of 1/(cos(2x)) ?

The derivative of 1/(cos(2x)) is sec(2x)tan(2x)*2

What is the first derivative of 1/(cos(2x)) ?

The first derivative of 1/(cos(2x)) is sec(2x)tan(2x)*2

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\frac{d}{d x} (\frac{1}{cos ( 2 x )})

sec (2 x) tan (2 x) \cdot 2

Solution steps

\frac{d}{d x} (\frac{1}{cos ( 2 x )})

Simplify

\frac{1}{cos ( 2 x )} : sec (2 x)

= \frac{d}{d x} (sec (2 x))

Apply the chain rule:

sec (2 x) tan (2 x) \frac{d}{d x} (2 x)

= sec (2 x) tan (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= sec (2 x) tan (2 x) \cdot 2

\int x^{2} 4 - x d x

\frac{d}{d x} ((9 x^{3} - 4 ln (x)) (7 e^{x} + 8 x))

\frac{\partial}{\partial y} (ln (\frac{x}{t}))

\int x e^{- y x} d x

\frac{d}{d x} (sin^{2} (x^{2} + 1))

What is the derivative of 1/(cos(2x)) ?
The derivative of 1/(cos(2x)) is sec(2x)tan(2x)*2
What is the first derivative of 1/(cos(2x)) ?
The first derivative of 1/(cos(2x)) is sec(2x)tan(2x)*2