What is the sum from x=1 to infinity of xsin(1/x) ?

The sum from x=1 to infinity of xsin(1/x) is diverges

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sum from x=1 to infinity of xsin(1/x)

x = 1 \sum \infty x sin (\frac{1}{x})

diverges

Solution steps

n = 1 \sum \infty n sin (\frac{1}{n})

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty e^{b l n (n)}

n = 1 \sum \infty 6 n e^{- n^{2}}

k = 1 \sum \infty \frac{8}{k ^{7} + 9}

n = 0 \sum \infty \frac{2 n}{5 n + 1}

n = 1 \sum \infty n e^{- \frac{n}{9}}

What is the sum from x=1 to infinity of xsin(1/x) ?
The sum from x=1 to infinity of xsin(1/x) is diverges