What is the sum from k=3 to infinity of 1/((k-2)^3) ?

The sum from k=3 to infinity of 1/((k-2)^3) is converges

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sum from k=3 to infinity of 1/((k-2)^3)

k = 3 \sum \infty \frac{1}{( k - 2 ) ^{3}}

converges

Solution steps

k = 3 \sum \infty \frac{1}{( k - 2 ) ^{3}}

Apply Series Integral Test:

converges

= converges

n = 0 \sum \infty \frac{i ^{2 n}}{2 n}

k = 1 \sum \infty \frac{1}{k k}

n = 0 \sum \infty 7 + \frac{5}{n ^{5}}

n = 1 \sum \infty (1.05)^{n}

n = 1 \sum \infty \frac{n}{4 n ^{3} + 3}

What is the sum from k=3 to infinity of 1/((k-2)^3) ?
The sum from k=3 to infinity of 1/((k-2)^3) is converges