Solution
Solution
Solution steps
Apply Series Ratio Test:converges
Popular Examples
sum from n=1 to infinity of (-1.99+1)^nsum from n=1 to infinity of 2/(n^{10)}sum from n=0 to infinity of (n^6)/(n!)sum from n=4 to infinity of 6^{-n}sum from n=0 to infinity of n*2
Frequently Asked Questions (FAQ)
What is the sum from k=1 to infinity of k^3e^{-2k} ?
The sum from k=1 to infinity of k^3e^{-2k} is converges