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Popular >

integral of 7/(2y^4)

Solution

\int \frac{7}{2 y ^{4}} d y

Solution

- \frac{7}{6 y ^{3}} + C

Solution steps

\int \frac{7}{2 y ^{4}} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{7}{2} \cdot \int \frac{1}{y ^{4}} d y

Apply the Power Rule

: - \frac{1}{3 y ^{3}}

= \frac{7}{2} (- \frac{1}{3 y ^{3}})

Simplify

\frac{7}{2} (- \frac{1}{3 y ^{3}}) : - \frac{7}{6 y ^{3}}

= - \frac{7}{6 y ^{3}}

Add a constant to the solution

= - \frac{7}{6 y ^{3}} + C

Popular Examples

y^'=(x^4y^4+4x^4)/(y^3)

y^{^{'}} = \frac{x ^{4} y ^{4} + 4 x ^{4}}{y ^{3}}

tangent of x^3+2x^2+4 tangent of

x^{3} + 2 x^{2} + 4

integral of (4^{sqrt(x)})/(sqrt(x))

\int \frac{4 ^{x}}{x} d x

y^{''}+9y=4sin(x)

y^{^{''}} + 9 y = 4 sin (x)

derivative of 1+sqrt(5x)

\frac{d}{d x} (1 + 5 x)

Frequently Asked Questions (FAQ)

What is the integral of 7/(2y^4) ?
The integral of 7/(2y^4) is -7/(6y^3)+C