Solution
Solution
Solution steps
Apply the constant multiplication rule:
Simplify
Popular Examples
sum from k=1 to infinity of 5/((k+4)^2)sum from n=0 to infinity of n^{1/3}sum from n=0 to infinity of n/(2^{n-1)}sum from n=1 to infinity of 1/(n(1+n))sum from n=0 to infinity of 3/(n^2+3)
Frequently Asked Questions (FAQ)
What is the sum from n=2 to infinity of 1/6 (5/6)^n ?
The sum from n=2 to infinity of 1/6 (5/6)^n is 25/36