What is the integral of 0.8sin(x)+(1.6)/(pi^2)x ?

The integral of 0.8sin(x)+(1.6)/(pi^2)x is -0.8cos(x)+0.08105…x^2+C

Popular >

integral of 0.8sin(x)+(1.6)/(pi^2)x

\int 0.8 sin (x) + \frac{1.6}{π ^{2}} x d x

- 0.8 cos (x) + 0.08105 \dots x^{2} + C

Solution steps

\int 0.8 sin (x) + \frac{1.6}{π ^{2}} x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 0.8 sin (x) d x + \int \frac{1.6}{π ^{2}} x d x

\int 0.8 sin (x) d x = - 0.8 cos (x)

\int \frac{1.6}{π ^{2}} x d x = 0.08105 \dots x^{2}

= - 0.8 cos (x) + 0.08105 \dots x^{2}

Add a constant to the solution

= - 0.8 cos (x) + 0.08105 \dots x^{2} + C

\frac{\partial}{\partial z} (tan (5 + 2 x^{2} y^{4} z^{2}))

\frac{d y}{d x} = 5^{t a n (5 x)}

y^{^{''}} - \frac{2}{t ^{2}} y = 0

\frac{\partial}{\partial x} (x^{3} sin (x^{2}))

\int_{1}^{2} \frac{9}{x ^{3} + 2 x} d x

What is the integral of 0.8sin(x)+(1.6)/(pi^2)x ?
The integral of 0.8sin(x)+(1.6)/(pi^2)x is -0.8cos(x)+0.08105…x^2+C