What is the integral from 0 to 1 of x^2 ?

The integral from 0 to 1 of x^2 is 1/3

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integral from 0 to 1 of x^2

\int_{0}^{1} x^{2} d x

\frac{1}{3}

Decimal Notation

0.33333 \dots

Solution steps

\int_{0}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{1}

= [\frac{x ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= \frac{1}{3}

\frac{\partial}{\partial x} (x e^{x y} cos (2 x) - 3)

\frac{d x}{d t} = cot (x) cos (t)

(x + 1) e^{x}

f (x) = \frac{5}{x ^{2}}

\frac{d}{d x} (x (3 x^{2} + 4 x - 9))

What is the integral from 0 to 1 of x^2 ?
The integral from 0 to 1 of x^2 is 1/3