What is the sum from n=0 to infinity of ln(1+5n) ?

The sum from n=0 to infinity of ln(1+5n) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of ln(1+5n)

n = 0 \sum \infty ln (1 + 5 n)

diverges

Solution steps

n = 0 \sum \infty ln (1 + 5 n)

Apply Series Divergence Test:

diverges

= diverges

n = 0 \sum \infty 3 (\frac{1}{11})^{n}

n = 1 \sum \infty (- \frac{6}{8})^{n - 1}

n = 0 \sum \infty \frac{1}{1 - 5 n}

n = 1 \sum \infty (\frac{3}{7})^{n - 1}

n = 6 \sum \infty \frac{1}{n} - \frac{1}{n + 2}

What is the sum from n=0 to infinity of ln(1+5n) ?
The sum from n=0 to infinity of ln(1+5n) is diverges