Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Divergence Test:diverges

Popular Examples

sum from n=1 to infinity of (n-2)/(n^2)sum from n=1 to infinity of (4^n)/(n^5)sum from n=1 to infinity of 7^nsum from n=1 to infinity of e^{-7n}sum from n=1 to infinity of 6e^{-n}

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of-5n ?

    The sum from n=1 to infinity of-5n is diverges