What is the sum from k=1 to infinity of k/(500k+5) ?

The sum from k=1 to infinity of k/(500k+5) is diverges

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sum from k=1 to infinity of k/(500k+5)

k = 1 \sum \infty \frac{k}{500 k + 5}

diverges

Solution steps

k = 1 \sum \infty \frac{k}{500 k + 5}

Apply Series Divergence Test:

diverges

= diverges

n = 8 \sum \infty \frac{2 n + 1}{n ^{n}}

n = 0 \sum \infty \frac{2}{( n + 1 ) ^{3}}

n = 1 \sum \infty (\frac{2}{n})^{n}

n = 3 \sum \infty \frac{4}{n ^{2} - n}

n = 0 \sum \infty \frac{1}{n ^{2} + 5 n + 4}

What is the sum from k=1 to infinity of k/(500k+5) ?
The sum from k=1 to infinity of k/(500k+5) is diverges