What is the sum from n=1 to infinity of sec(n) ?

The sum from n=1 to infinity of sec(n) is diverges

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sum from n=1 to infinity of sec(n)

n = 1 \sum \infty sec (n)

diverges

Solution steps

n = 1 \sum \infty sec (n)

Apply Series Divergence Test:

diverges

= diverges

n = 0 \sum \infty \frac{2}{5}

n = 0 \sum \infty \frac{2}{3 + n}

n = 1 \sum \infty \frac{2}{7 ^{n} + 1}

n = 0 \sum \infty 10 \cdot 9.14

n = 1 \sum \infty \frac{n ^{2}}{5 n ^{2}}

What is the sum from n=1 to infinity of sec(n) ?
The sum from n=1 to infinity of sec(n) is diverges