What is the sum from n=1 to infinity of 8n+1 ?

The sum from n=1 to infinity of 8n+1 is diverges

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sum from n=1 to infinity of 8n+1

n = 1 \sum \infty 8 n + 1

diverges

Solution steps

n = 1 \sum \infty 8 n + 1

Apply Series Divergence Test:

diverges

= diverges

n = 0 \sum \infty sin (e^{- n})

n = 1 \sum \infty 2 (- \frac{1}{7})^{2 n}

n = 1 \sum \infty \frac{1 9 ^{n}}{n !}

k = 0 \sum \infty \frac{2}{k ^{2} + k}

n = 1 \sum \infty \frac{1}{5 ^{3 n}}

What is the sum from n=1 to infinity of 8n+1 ?
The sum from n=1 to infinity of 8n+1 is diverges