What is the sum from n=0 to infinity of e^{1/2} ?

The sum from n=0 to infinity of e^{1/2} is diverges

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sum from n=0 to infinity of e^{1/2}

n = 0 \sum \infty e^{\frac{1}{2}}

diverges

Solution steps

n = 0 \sum \infty e^{\frac{1}{2}}

Every infinite sum of a non-zero constant diverges

= diverges

n = 1 \sum \infty \frac{1}{ln ( 5 ^{n} )}

n = 0 \sum \infty (\frac{1}{1.02})^{n}

k = 2 \sum \infty \frac{k}{k ^{3} - k + 1}

n = 2 \sum \infty \frac{2}{n \cdot ( n + 2 )}

n = 2 \sum \infty cos (\frac{1}{n})

What is the sum from n=0 to infinity of e^{1/2} ?
The sum from n=0 to infinity of e^{1/2} is diverges