What is the sum from n=0 to infinity of (3/n)^{3/n} ?

The sum from n=0 to infinity of (3/n)^{3/n} is diverges

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sum from n=0 to infinity of (3/n)^{3/n}

n = 0 \sum \infty (\frac{3}{n})^{\frac{3}{n}}

diverges

Solution steps

n = 1 \sum \infty (\frac{3}{n})^{\frac{3}{n}}

Apply Series Divergence Test:

diverges

= diverges

k = n \sum \infty (\frac{3}{4})^{k} (\frac{1}{4})

n = 0 \sum \infty 4 (\frac{8}{9})^{n}

n = 1 \sum \infty cos (n)

n = 1 \sum \infty \frac{n !}{1 1 ^{n}}

n = 0 \sum \infty n^{2} - 2

What is the sum from n=0 to infinity of (3/n)^{3/n} ?
The sum from n=0 to infinity of (3/n)^{3/n} is diverges