What is the sum from n=0 to infinity of ((-1)/7)^n ?

The sum from n=0 to infinity of ((-1)/7)^n is 7/8

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sum from n=0 to infinity of ((-1)/7)^n

n = 0 \sum \infty (\frac{- 1}{7})^{n}

\frac{7}{8}

Solution steps

n = 0 \sum \infty (\frac{- 1}{7})^{n}

Apply Series Geometric Test:

\frac{7}{8}

= \frac{7}{8}

n = 1 \sum \infty 8 (0.3)^{n - 1}

n = 0 \sum \infty \frac{10}{n ^{2} + 9}

b = 0 \sum \infty 9 (\frac{2}{3})^{b}

n = 0 \sum \infty \frac{( - 2 ) ^{n}}{n}

n = 1 \sum \infty \frac{n}{5 n ^{3} + 3}

What is the sum from n=0 to infinity of ((-1)/7)^n ?
The sum from n=0 to infinity of ((-1)/7)^n is 7/8