What is implicit (dy)/(dx),ln(xy)+9x=40 ?

The answer to implicit (dy)/(dx),ln(xy)+9x=40 is (dy}{dx}=\frac{-9xy-y)/x

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implicit (dy)/(dx),ln(xy)+9x=40

implicit derivative

\frac{d y}{d x}, ln (x y) + 9 x = 40

\frac{d y}{d x} = \frac{- 9 x y - y}{x}

Solution steps

ln (x y) + 9 x = 40

Treat

y

y (x)

Differentiate both sides:

\frac{y + x \frac{d y}{d x}}{x y} + 9 = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{- 9 x y - y}{x}

\frac{d y}{d x} = \frac{- 9 x y - y}{x}

\int \frac{16 y - 9}{3 y - 5 y ^{2}} d y

\int x^{1} cos (- 9 x) d x

x \to 3 lim (\frac{∣ x - 2 ∣}{x - 2})

y = \frac{4 x ^{7}}{7}

\frac{d}{d x} (e^{3 x - 5})

What is implicit (dy)/(dx),ln(xy)+9x=40 ?
The answer to implicit (dy)/(dx),ln(xy)+9x=40 is (dy}{dx}=\frac{-9xy-y)/x