Solution
Solution
Solution steps
Apply the constant multiplication rule:
Apply Cauchy's Convergence Condition:diverges
Popular Examples
sum from n=1 to infinity of n/(6n^3+5)sum from n=0 to infinity of 5n^2sum from n=2 to infinity of 1/(3n+4)sum from n=1 to infinity of 3(0.4)^{n-1}sum from n=3 to infinity of 1/(5^n)
Frequently Asked Questions (FAQ)
What is the sum from n=1 to infinity of (sin(1))/n ?
The sum from n=1 to infinity of (sin(1))/n is diverges