What is the derivative of x^2+4x-1 ?

The derivative of x^2+4x-1 is 2x+4

What is the first derivative of x^2+4x-1 ?

The first derivative of x^2+4x-1 is 2x+4

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derivative of

x^{2} + 4 x - 1

2 x + 4

Solution steps

\frac{d}{d x} (x^{2} + 4 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 2 x + 4 - 0

Simplify

= 2 x + 4

\int (2 x^{2} + 3 x - 2) (4 x + 3) d x

\int_{1}^{2} 12 x^{2} 3^{x^{3}} d x

\int \frac{( a + b x ^{2} )}{3 a x + b x ^{3}} d x

\int_{- 1}^{0} y + 1 d y

y^{^{'}} = 2 t, y (0) = 0

What is the derivative of x^2+4x-1 ?
The derivative of x^2+4x-1 is 2x+4
What is the first derivative of x^2+4x-1 ?
The first derivative of x^2+4x-1 is 2x+4