What is the sum from n=0 to infinity of (1+6/n)^n ?

The sum from n=0 to infinity of (1+6/n)^n is diverges

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sum from n=0 to infinity of (1+6/n)^n

n = 0 \sum \infty (1 + \frac{6}{n})^{n}

diverges

Solution steps

n = 1 \sum \infty (1 + \frac{6}{n})^{n}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty 9 (0.9)^{n - 1}

n = 1 \sum \infty \frac{3}{n ^{\frac{1}{2}}}

n = 0 \sum \infty \frac{2}{n ^{3} + 5}

n = 0 \sum \infty cos (\frac{1}{n + 1})

k = 6 \sum \infty \frac{1}{( k - 5 ) ^{4}}

What is the sum from n=0 to infinity of (1+6/n)^n ?
The sum from n=0 to infinity of (1+6/n)^n is diverges