What is the sum from n=1 to infinity of (0)^n ?

The sum from n=1 to infinity of (0)^n is Undefined

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of (0)^n

n = 1 \sum \infty (0)^{n}

Undefined

Solution steps

n = 1 \sum \infty 0^{n}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty 0^{n} - 0^{0}

n = 0 \sum \infty 0^{n} = 1

= 1 - 0^{0}

0^{0}

is undefined

= Undefined

n = 1 \sum \infty - \frac{1}{1 4 ^{n}}

n = 0 \sum \infty \frac{2 n}{2 n + 1}

n = 0 \sum \infty \frac{i}{3 ^{n}}

n = 0 \sum \infty \frac{n}{1 - n}

k = 2 \sum \infty (\frac{4}{5})^{3 k}

What is the sum from n=1 to infinity of (0)^n ?
The sum from n=1 to infinity of (0)^n is Undefined