Solution

Solution

Solution steps
Apply the constant multiplication rule:
Apply Series Divergence Test:diverges

Popular Examples

sum from n=2 to infinity of 1/n-1/(n+3)sum from n=0 to infinity of n/(1+8n^3)sum from n=1 to infinity of 10sum from n=1 to infinity of (2n)/(3n+5)sum from n=1 to infinity of 2ne^{-n}

Frequently Asked Questions (FAQ)

  • What is the sum from n=1 to infinity of 4n ?

    The sum from n=1 to infinity of 4n is diverges