What is the sum from n=1 to infinity of 1/(n^7+2) ?

The sum from n=1 to infinity of 1/(n^7+2) is converges

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sum from n=1 to infinity of 1/(n^7+2)

n = 1 \sum \infty \frac{1}{n ^{7} + 2}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{7} + 2}

Apply Series Comparison Test:

converges

= converges

k = 0 \sum \infty \frac{k}{1 + k ^{4}}

n = 1 \sum \infty \frac{5}{n ^{0.6}}

n = 1 \sum \infty \frac{1}{4 n + 5}

n = 0 \sum \infty \frac{3}{2 ^{n + 1}}

n = 0 \sum \infty \frac{n}{n ^{2} + n}

What is the sum from n=1 to infinity of 1/(n^7+2) ?
The sum from n=1 to infinity of 1/(n^7+2) is converges