What is the sum from n=1 to infinity of (e^n)/(e^n) ?

The sum from n=1 to infinity of (e^n)/(e^n) is diverges

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sum from n=1 to infinity of (e^n)/(e^n)

n = 1 \sum \infty \frac{e ^{n}}{e ^{n}}

diverges

Solution steps

n = 1 \sum \infty \frac{e ^{n}}{e ^{n}}

Simplify

= n = 1 \sum \infty 1

Every infinite sum of a non-zero constant diverges

= diverges

n = 1 \sum \infty \frac{10}{2 ^{n}}

n = 0 \sum \infty \frac{7}{4 - n ^{2}}

n = 1 \sum \infty n (\frac{1}{4})^{n}

k = 1 \sum \infty \frac{5}{k + 6}

n = 1 \sum \infty \frac{1}{n} - \frac{1}{n + 5}

What is the sum from n=1 to infinity of (e^n)/(e^n) ?
The sum from n=1 to infinity of (e^n)/(e^n) is diverges