What is the sum from n=0 to infinity of ((-3)/4)^n ?

The sum from n=0 to infinity of ((-3)/4)^n is 4/7

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sum from n=0 to infinity of ((-3)/4)^n

n = 0 \sum \infty (\frac{- 3}{4})^{n}

\frac{4}{7}

Solution steps

n = 0 \sum \infty (\frac{- 3}{4})^{n}

Apply Series Geometric Test:

\frac{4}{7}

= \frac{4}{7}

n = 1 \sum \infty \frac{5}{n ^{2} + 1}

k = 2 \sum \infty 9 e^{- 2 k}

k = 2 \sum \infty (\frac{1}{3})^{3 k}

n = 1 \sum \infty (0)^{n - 1}

k = 2 \sum \infty (- 0.9)^{k}

What is the sum from n=0 to infinity of ((-3)/4)^n ?
The sum from n=0 to infinity of ((-3)/4)^n is 4/7