What is the sum from n=5 to infinity of cos(1/(n+1)) ?

The sum from n=5 to infinity of cos(1/(n+1)) is diverges

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sum from n=5 to infinity of cos(1/(n+1))

n = 5 \sum \infty cos (\frac{1}{n + 1})

diverges

Solution steps

n = 5 \sum \infty cos (\frac{1}{n + 1})

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty (\frac{3}{n})^{n}

n = 1 \sum \infty (\frac{4}{25})^{n}

n = 1 \sum \infty \frac{1}{( 1 + n )}

n = 1 \sum \infty \frac{n + 3}{8 ^{n}}

n = 0 \sum \infty \frac{k}{2 ^{n}}

What is the sum from n=5 to infinity of cos(1/(n+1)) ?
The sum from n=5 to infinity of cos(1/(n+1)) is diverges