What is the sum from n=1 to infinity of 1/2+4/(3^n) ?

The sum from n=1 to infinity of 1/2+4/(3^n) is diverges

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sum from n=1 to infinity of 1/2+4/(3^n)

n = 1 \sum \infty \frac{1}{2} + \frac{4}{3 ^{n}}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{2} + \frac{4}{3 ^{n}}

Apply Series Divergence Test:

diverges

= diverges

n = 1 \sum \infty 3 n (\frac{1}{4})^{n}

n = 0 \sum \infty cos (2 nπ)

n = 0 \sum \infty \frac{15}{4} (\frac{1}{4})^{n}

n = 1 \sum \infty \frac{1}{2 ^{n} - 9}

n = 7 \sum \infty \frac{1}{n ( n + 1 )}

What is the sum from n=1 to infinity of 1/2+4/(3^n) ?
The sum from n=1 to infinity of 1/2+4/(3^n) is diverges