What is the sum from k=0 to infinity of (-4/7)^k ?

The sum from k=0 to infinity of (-4/7)^k is 7/11

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sum from k=0 to infinity of (-4/7)^k

k = 0 \sum \infty (- \frac{4}{7})^{k}

\frac{7}{11}

Solution steps

k = 0 \sum \infty (- \frac{4}{7})^{k}

Apply Series Geometric Test:

\frac{7}{11}

= \frac{7}{11}

n = 0 \sum \infty sin (\frac{πn}{2})

n = 1 \sum \infty \frac{( 0.99 ) ^{n}}{n}

k = 0 \sum \infty 3 (- \frac{1}{4})^{k}

n = 1 \sum \infty \frac{3}{5 n + 1}

i = 1 \sum \infty 7 + 3 i

What is the sum from k=0 to infinity of (-4/7)^k ?
The sum from k=0 to infinity of (-4/7)^k is 7/11